题解 | #删除字符串中出现次数最少的字符#

let input;
while (input = readline()) {
    let str = input;
    let child = []; // 用于存入每个不同的字符
    let minArr = []; // 出现次数最少的字符
    let min = str.length; // 最少次数
    for (let i = 0; i < str.length; i++) {
        if (child.indexOf(str[i]) === -1) {
            child.push(str[i]);
            let j = i + 1;
            let count = 1;
            while (j < str.length) {
                if (str[i] === str[j]) {
                    count++;
                }
                j++;
            }
            if (count < min) {
                min = count;
                minArr = [];
                minArr.push(str[i]);
            } else if (count === min) {
                minArr.push(str[i]);
            }
        }
        
    }
    // 删除字符串中出现次数最少的字符
    let result = str.split('').filter(item => {
        return minArr.indexOf(item) === -1;
    });
    
    print(result.join(''));
}