//递归输出LCS
#include<iostream>
#include<cstring>
#include<vector>
#include<algorithm>
using namespace std;
const int N = 2e3+9;
char s[N],t[N];
int dp[N][N];
int path[N][N];
void print(int i,int j)
{
if(i == 0 || j == 0) return;
if(path[i][j] == 1)
{
print(i-1,j-1);
printf("%c",s[i]);
}
else if(path[i][j] == 2)
{
print(i-1,j);
}
else if(path[i][j] == 3)
{
print(i,j-1);
}
}
int main()
{
scanf("%s%s",s+1,t+1);
int n = strlen(s+1),m = strlen(t+1);
for(int i=1; i<=n; i++)
{
for(int j=1; j<=m; j++)
{
if(s[i] == t[j])
{
dp[i][j] = dp[i-1][j-1] + 1;
path[i][j] = 1;
}
else if(dp[i-1][j] >= dp[i][j-1])
{
dp[i][j] = dp[i-1][j];
path[i][j] = 2;
}
else
{
dp[i][j] = dp[i][j-1];
path[i][j] = 3;
}
}
}
print(n,m);
return 0;
}