-- 部门平均绩效得分
select
e.employee_id,
department_name,
performance_score
from employee_projects e
join
(select
employee_id,
department_name,
avg(performance_score) over(partition by department_name)as avg_performance_score
from employee_projects e
join department_info d using(employee_id)
group by 1,2)t
on e.employee_id=t.employee_id
where performance_score>avg_performance_score
order by 1;



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