SELECT level_cut,COUNT(issue_id) num FROM( SELECT issue_id, CASE WHEN author_level BETWEEN 1 AND 2 THEN '1-2级' WHEN author_level BETWEEN 3 AND 4 THEN '3-4级' ELSE '5-6级' END AS level_cut FROM author_tb JOIN answer_tb USING(author_id) WHERE char_len>=100 )t2 GROUP BY level_cut ORDER BY num DESC;
不是计算用户数量
而是回答的数量



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