#include <iostream>
#include<queue>
#include<cstdio>
#include<cstring>
#include<string>
#include<cmath>//求次幂,是pow,不是power
//这题是假定a和b都是正整数吗?
using namespace std;
typedef struct Complex {
int a;
int b;
Complex();
Complex(int a0, int b0): a(a0), b(b0) {};
friend bool operator<(const Complex& c1, const Complex& c2);
friend ostream& operator<<(ostream& out, const Complex& c);
};
Complex::Complex() {
}
//一般将双目运算符重载为友元函数
priority_queue<Complex> plur;
bool operator<(const Complex& c1, const Complex& c2) {
bool tag=false;
if (pow(c1.a, 2) + pow(c1.b, 2) < pow(c2.a, 2) + pow(c2.b, 2)) {
tag=true;
} else if (pow(c1.a, 2) + pow(c1.b, 2) == pow(c2.a, 2) + pow(c2.b, 2)) {
tag=c1.b > c2.b;//!!输出b较小的
}//不用再有else了
return tag;
}
ostream& operator<<(ostream& out, const Complex& c) {
out << c.a << "+i" << c.b;
return out;
}
int Insert(string str) {
int pos = str.find('i');
string stra = str.substr(0, pos - 1); //不包括第二个位置的数
string strb = str.substr(pos + 1);
// cout<<"a="<<stra<<"b="<<strb<<endl;
int a = 0, b = 0;
for (int i = 0; i < stra.size(); i++) {
a = a * 10 + stra[i] - '0';
}
// cout<<a<<endl;
for (int j = 0; j < strb.size(); j++) {
b = b * 10 + strb[j] - '0';
}
// cout<<b<<endl;
Complex s = Complex(a, b);
plur.push(s);
return plur.size();
}
string counterpart(string str) {
string strRes;
if (str[0] == 'P') {
strRes = str;
} else if (str[0] == 'I') {
strRes = str.substr(7);
}
return strRes;
}
int main() {
int n;
while (scanf("%d", &n) != EOF) {
cin.ignore();
//!!!scanf函数或cin函数有回车符,
//使用getline会导致直接跳过,所以要在这里加上cin.ignore()
while (n > 0) {
string str;
getline(cin, str);
string commend = counterpart(str);
if (commend == "Pop") {
if (plur.empty()) {
cout << "empty" << endl; //加endl换行
} else {
Complex res = plur.top();
plur.pop();
cout << res << endl;;
cout << "SIZE = " << plur.size() << endl;
}
} else {
cout << "SIZE = " << Insert(commend) << endl;
}
n--;
}
}
return 0;
}