只要找到一个质数,就从它的2次幂往答案里面加就行了,只要幂值不超过n:
import java.util.*;
public class Main {
public static void main(String[] args) throws Exception{
Scanner sc = new Scanner(System.in);
int n = sc.nextInt();
Set<Integer> r = new HashSet<>();
for(int i = 2; i <= n; ++i){
if(f(i)){
r.add(i);
for(int j = 2;; ++j){
int p = (int)Math.pow(i, j);
if(p > n) break;
r.add(p);
}
}
}
System.out.println(r.size());
}
static boolean f(int n){ //暴力筛质数
if(n <= 1) return false;
if(n == 2) return true;
for(int i = 2; i < n; ++i){
if(n%i == 0) return false;
}
return true;
}
}
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