题解 | #记负均正#

# !/usr/bin/env python3
# -*- coding: utf-8 -*-
__author__ = 'tianyi'
__date__ = '2024/3/25 10:15 '
__file__ = 'HW_HJ97.py'

import sys
# 1. 读取输入
count = 0
count_0 = 0
total = 0
less_0 = 0
for i   in sys.stdin:
    i = [int(n) for n in i.split()]
    if len(i) > 1:
        for j in i:
            if j > 0:
                total += j
            elif j < 0:
                less_0 += 1
            else:
                count_0 += 1
    elif len(i) == 1:
        count = i[0]
#total保留一位小数.兼容分母为0的情况
if count_0 == count:
    print(str(less_0)+" "+str(0.0))
else:
    print(str(less_0)+" "+str(round(total/(count-less_0-count_0),1)))