题解 | #求int型正整数在内存中存储时1的个数#

const rl = require("readline").createInterface({ input: process.stdin });
var iter = rl[Symbol.asyncIterator]();
const readline = async () => (await iter.next()).value;

void (async function () {
    while ((line = await readline())) {
        // 先转成2进制数
        const number = String(Number(line).toString(2));
        // 统计1的数量
        const number_length = number.length;
        let count = 0;
        for (let i = 0; i < number_length; i++) {
            if (number[i] == 1) {
                count++;
            }
        }
        console.log(count)
    }
})();