#include<stdio.h>
int main()
{
int a = 40;
int c = 212;
//输出
printf("%d\n", (-8 + 22) * a - 10 + c / 2);
return 0;
}
#include<stdio.h>
int main()
{
int a = 40;
int c = 212;
//输出
printf("%d\n", (-8 + 22) * a - 10 + c / 2);
return 0;
}