select e.emp_no,s.salary,e.last_name,e.first_name
from employees e,salaries s,(
select max(salary) salary
from salaries
where salary != (
select max(salary) salary
from salaries
) # firstMax
) secondMax
where e.emp_no = s.emp_no and s.salary = secondMax.salary把最大工资排除后,剩下数据的最大工资就是第二工资

京公网安备 11010502036488号