题解 | #删除有序链表中重复的元素-I#

/**
 * struct ListNode {
 *	int val;
 *	struct ListNode *next;
 * };
 */
/**
 * 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
 *
 * 
 * @param head ListNode类 
 * @return ListNode类
 */
struct ListNode* deleteDuplicates(struct ListNode* head ) {
    // write code here
    if(head==NULL)
    return NULL;
    if(head->next==NULL)
    return head;
    struct ListNode *cur1=head,*cur2=head->next;

    while(cur2)
    {
        if(cur1->val!=cur2->val)
        {
cur1=cur1->next;
cur2=cur2->next;
        }
        else{
            cur2=cur2->next;
            cur1->next=cur2;
        }
       
}
return head;
}