题解 | #简单错误记录#

解题思路

1. import java.io.BufferedReader;
   import java.io.IOException;
   import java.io.InputStreamReader;
   public class Main1 {
   
    public static void main(String[] args) throws IOException {
   
        BufferedReader reader = new BufferedReader(new InputStreamReader(System.in));
        String input = null;
        StringBuffer sb = new StringBuffer();
   
        while (null != (input = reader.readLine())) {
   
            //设置四种类型数据初始为空即false，有数据了就更改为true
            boolean[] flag = new boolean[4];
            char[] chars = input.toCharArray();
   
            // 第一个条件
            if (chars.length < 9) {
                sb.append("NG").append("\n");
                continue;
            }
   
            // 第二个条件
            for (int i = 0; i < chars.length; i++) {
                if ('A' <= chars[i] && chars[i] <= 'Z') {
                    flag[0] = true;
                } else if ('a' <= chars[i] && chars[i] <= 'z') {
                    flag[1] = true;
                } else if ('0' <= chars[i] && chars[i] <= '9') {
                    flag[2] = true;
                } else {
                    flag[3] = true;
                }
            }
            int count = 0;
            for (int i = 0; i < 4; i++) {
                if (flag[i]) {
                    count++;
                }
            }
   
            // 第三个条件
            boolean sign = true;        //不存在两个大于2的子串相同，即！（i=i+3,i+1=i+4,i+2=i+5）
            for (int i = 0; i < chars.length - 5; i++) {
                for (int j = i + 3; j < chars.length - 2; j++) {
                    if (chars[i] == chars[j] && chars[i + 1] == chars[j + 1] && chars[i + 2] == chars[j + 2]) {
                        sign = false;
                    }
                }
            }
   
            if (count >= 3 && sign) {
                sb.append("OK").append("\n");
            } else {
                sb.append("NG").append("\n");
            }
        }
        String string = sb.toString();
        System.out.println( string.trim());
   
    }
   }