题解 | 仰望水面的歪

#include <iostream>
#include <vector>
#include <numeric>
using namespace std;


long  gcd3(long a, long b, long c) {
    return gcd(gcd(abs(a), abs(b)), abs(c));
}

int main() {
    int n;
    long  h;
    cin >> n >> h;

    while (n--) {
        long  x, y, z;
        cin >> x >> y >> z;

        long  i = x;
        long  j = y;
        long  k = 2 * h - z;

        long  g = gcd3(i, j, k);

        // 化简使得 gcd(i, j, k) = 1
        i /= g;
        j /= g;
        k /= g;

        cout << i << " " << j << " " << k << endl;
    }

    return 0;
}