Solution
spfa找正环
Code
#include<bits/stdc++.h>
using namespace std;
typedef long long ll;
int b[102][1002],s[102][1002],i,j,k,K,tot,n,m,mp[102][102],q[990001],L[102],x,y,z,l,r,mid,T[102][1002],ans;
ll dis[102];
bool vis[102];
inline char gc(){
static char buf[100000],*p1=buf,*p2=buf;
return p1==p2&&(p2=(p1=buf)+fread(buf,1,100000,stdin),p1==p2)?EOF:*p1++;
}
inline int rd(){
int x=0,fl=1;char ch=gc();
for (;ch<48||ch>57;ch=gc())if(ch=='-')fl=-1;
for (;48<=ch&&ch<=57;ch=gc())x=(x<<3)+(x<<1)+(ch^48);
return x*fl;
}
bool chk(int x){
memset(L,0,(n+1)<<2);
memset(dis,0,(n+1)<<3);
int h=0,t=0;
for (int i=1;i<=n;i++) q[t++]=i,vis[i]=1;
while (h<t){
int u=q[h++];vis[u]=0;
for (int i=1;i<=n;i++)
if (dis[i]<=dis[u]+T[u][i]-1ll*x*mp[u][i]){
dis[i]=dis[u]+T[u][i]-1ll*x*mp[u][i];
if (!vis[i]){
if ((++L[i])==n) return 1;
vis[i]=1,q[t++]=i;
}
}
}
return 0;
}
int main(){
n=rd();m=rd();K=rd();
memset(mp,63,sizeof(mp));
for (i=1;i<=n;i++)
for (j=1;j<=K;j++) b[i][j]=rd(),s[i][j]=rd();
for (i=1;i<=n;i++)
for (j=1;j<=n;j++)
for (k=1;k<=K;k++)
if (b[i][k]!=-1 && s[j][k]!=-1) T[i][j]=max(T[i][j],s[j][k]-b[i][k]);
for (i=1;i<=m;i++) x=rd(),y=rd(),z=rd(),mp[x][y]=min(mp[x][y],z);
for (k=1;k<=n;k++)
for (i=1;i<=n;r=max(r,mp[i][j]),i++)
for (j=1;j<=n;j++) mp[i][j]=min(mp[i][j],mp[i][k]+mp[k][j]);
while (l<=r){
mid=l+r>>1;
if (chk(mid)) ans=mid,l=mid+1;
else r=mid-1;
}
printf("%d",ans);
}