思路:
1.快速排序的三路法
2.使得区间内 [left, lt) > value, [lt, gt) == value, [gt, right] < value
3.如果k-1 在 [lt, gt)之间,那就找到了第K大的数
4.主要是注意排序的规则
import java.util.*;
public class Solution {
public int findKth(int[] a, int n, int K) {
// write code here
if(a == null ||a.length < 1){
return -1;
}
int left = 0;
int right = a.length - 1;
return part(a, left, right, K-1);
}
private int part(int[] data, int left, int right, int K){
int index = new Random().nextInt(right - left +1);
int value = data[index+left];
data[index+left] = data[left];
data[left] = value;
int lt = left;
int gt = right + 1;
int i = left + 1;
while(i < gt){
if(data[i] < value){
int temp = data[gt-1];
data[gt-1] = data[i];
data[i] = temp;
gt --;
}else if(data[i] > value){
int temp = data[lt];
data[lt] = data[i];
data[i] = temp;
i++;
lt++;
}else{
i++;
}
}
if(lt <= K && K < gt){
return data[K];
}
if(lt > K){
//左边
return part(data, left, lt -1, K);
}else{
return part(data, gt , right, K);
}
}
}