7-36 复数四则运算 (15 point(s))
本题要求编写程序,计算2个复数的和、差、积、商。
输入格式:
输入在一行中按照a1 b1 a2 b2的格式给出2个复数C1=a1+b1i和C2=a2+b2i的实部和虚部。题目保证C2不为0。
输出格式:
分别在4行中按照(a1+b1i) 运算符 (a2+b2i) = 结果的格式顺序输出2个复数的和、差、积、商,数字精确到小数点后1位。如果结果的实部或者虚部为0,则不输出。如果结果为0,则输出0.0。
输入样例1:
2 3.08 -2.04 5.06
输出样例1:
(2.0+3.1i) + (-2.0+5.1i) = 8.1i
(2.0+3.1i) - (-2.0+5.1i) = 4.0-2.0i
(2.0+3.1i) * (-2.0+5.1i) = -19.7+3.8i
(2.0+3.1i) / (-2.0+5.1i) = 0.4-0.6i
输入样例2:
1 1 -1 -1.01
输出样例2:
(1.0+1.0i) + (-1.0-1.0i) = 0.0
(1.0+1.0i) - (-1.0-1.0i) = 2.0+2.0i
(1.0+1.0i) * (-1.0-1.0i) = -2.0i
(1.0+1.0i) / (-1.0-1.0i) = -1.0
思路:
不难,但是有点麻烦需要注意的是如果数值的绝对值小于0.1,即等于0,运算不难,主要在数值的输入,输出上面有点坑
#include <bits/stdc++.h>
using namespace std;
struct num{
double real;
double image;
};
num c1, c2;
void print(double a, double b, char c) {
bool flag = false;
if (c1.image >= 0 && c2.image >=0)
printf("(%.1lf+%.1lfi) %c (%.1lf+%.1lfi) = ", c1.real, c1.image, c, c2.real, c2.image);
else if (c1.image >= 0 && c2.image < 0)
printf("(%.1lf+%.1lfi) %c (%.1lf%.1lfi) = ", c1.real, c1.image, c, c2.real, c2.image);
else if (c1.image < 0 && c2.image >= 0)
printf("(%.1lf%.1lfi) %c (%.1lf+%.1lfi) = ", c1.real, c1.image, c, c2.real, c2.image);
else
printf("(%.1lf%.1lfi) %c (%.1lf%.1lfi) = ", c1.real, c1.image, c, c2.real, c2.image);
if (fabs(a) < 0.1 && fabs(b) < 0.1) {
cout << "0.0\n";
return ;
}
if (fabs(a) >= 0.1) {
printf("%.1lf", a);
flag = true;
}
if (fabs(b) >= 0.1) {
if(flag && b > 0.0) printf("+%.1lfi", b);
else printf("%.1lfi", b);
}
cout << endl;
}
void add(num a, num b) {
double really = a.real + b.real;
double imagen = a.image + b.image;
print(really, imagen, '+');
}
void minu(num a, num b) {
double really = a.real - b.real;
double imagen = a.image - b.image;
print(really, imagen, '-');
}
void multi(num a, num b) {
double really = - a.image * b.image + a.real * b.real;
double imagen = a.image * b.real + a.real * b.image;
print(really, imagen, '*');
}
void divide(num a, num b) {
double di = b.real * b.real + b.image * b.image;
double really = (a.image * b.image + a.real * b.real) / di;
double imagen = (a.image * b.real - a.real * b.image) / di;
print(really, imagen, '/');
}
int main() {
cin >> c1.real >> c1.image >> c2.real >> c2.image;
add(c1, c2);
minu(c1, c2);
multi(c1, c2);
divide(c1, c2);
return 0;
}