题解 | 简单错误记录

import sys

"""
知识点：
1. 转义字符\的处理
2. 如何自定义循环例如从列表的最后一个向前遍历？
"""
# 存储输入
count = sys.stdin.read().strip().split("\n")
# count = count[:len(count)-1]
# print(count)  # ['D:\\oblemsinnowcoder 12', 'D:\\nowcoderproblemsinnowcoder 12', 'D:\\nowcoder\\problemsinnowcoder 13', 'D:\\oj\\problemsinnowcoder 13']
count2 = []  # 用来存储中间结果
# 去掉多余信息
# 遍历所有报错地址
for i in range(len(count)):
    str1 = str(count[i])
    # 遍历每个报错地址的字符
    j = 0
    while '\\' in str1:
        
        if str1[j] == '\\' :
            str1 = str1[j+1:]
            j = 0
        j += 1
            
    # print(str1)
    
    for g in range(len(str1)):
        tag = 0  # 记录空格位置
        if str1[g] == ' ':
            tag = g
            # 如果大于16则截断
            if len(str1[:g]) > 16:
                str1 = str1[tag-16:]
                break
    # print(str1)
    count2.append(str1)
# print(count2)  # ['oblemsinnowcoder 12', 'oblemsinnowcoder 12', 'oblemsinnowcoder 13', 'oblemsinnowcoder 13']

# 输出不重复的报错地址
t = [] # 计数器
count3 = []
for i in range(len(count2)):
    if count2[i] not in count3:
        count3.append(count2[i])
        t.append(1)
    else:
        for p in range(len(count3)):
            if count2[i] == count3[p]:
                t[p] += 1
# 输出最后8条 
# print(count3)  # ['oblemsinnowcoder 12', 'oblemsinnowcoder 13']
if len(count3) > 8:
    count3 = count3[-8:]
    t = t[-8:]
for i in range(len(count3)):
    print(count3[i],t[i],sep=' ')