题解 | #简单密码#

#include <iostream>
#include <string>
#include <cstdio>

using namespace std;

int main() {
    string start, str, end;
    while (getline(cin,str)) {
        if (start == "ENDOFINPUT") {
            break;
        }
        getline(cin, str);
        for (int i = 0; i < str.size(); i++) {
            if (str[i] <= 'Z' && str[i] >= 'A') {
                str[i] = 'A' + ((str[i] - 'A' - 5) + 26) % 26;
            }
        }
        cout << str << endl;
        cin >> end;
    }
    return 0;
}
// 64 位输出请用 printf("%lld")

cin>>str换行不算字符串结尾，只有空格才算结尾

getline(cin,str)换行才算结尾