#include <iostream>
#include<vector>
#include<algorithm>
using namespace std;
int main() {
int n;
cin>>n;
int a[100000];
long long sum=0;
vector<int> odds;
for (int i = 0; i<n; i++) {
cin>>a[i];
sum+=a[i];//直接累加,最后总和是不是偶数
if (a[i]%2==1) {
odds.push_back(a[i]);
}
}
if (sum%2==0) {
cout<<sum<<endl;
}
else if (odds.empty()) {
cout<<0<<endl;
}
else {
sort(odds.begin(), odds.end());//移除里面最小的奇数。让总数为最大偶数
cout << sum - odds[0] << endl;
}
}
有点难,直接求总数再判断,用vector写更好看,也可以直接找最小奇数、直接判断有没有偶数:
#include <iostream>
#include <climits>
using namespace std;
int main() {
int n, x, minOdd = INT_MAX;
long long sum = 0;
cin >> n;
for (int i = 0; i < n; i++) {
cin >> x;
sum += x;
if (x % 2 == 1) minOdd = min(minOdd, x);
}
if (sum % 2 == 0) cout << sum << endl;
else if (minOdd == INT_MAX) cout << 0 << endl;
else cout << sum - minOdd << endl;
return 0;
}

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