题解 | #鸡兔同笼#

#include<stdio.h>
int main() {
    int n;
    while( scanf("%d", &n)!=EOF){
    int min = 99999999, max = 0, flag = 0;
   
    for (int i = 0; i < n; i++) //鸡个数  鸡最多a/2个
        for (int j = 0; j < n; j++) //兔个数 兔最多a/4个
            if (n == i * 2 + j * 4) {
                flag = 1;
                int count = i + j;
                if (count > max)
                    max = count;
                if (count < min)
                    min = count;

            }
    if (flag == 1)
        printf("%d %d\n", min, max);
    else printf("0 0\n");
}
    return 0;
}