#找到了id跟总分

select b.name,a.add0
from
        (
            #add
            select user_id,sum(grade_num) add0
            from grade_info 
            where type='add'
            group by user_id
        ) a left  join user b
        on a.user_id=b.id
       order by a.add0 desc
       limit 1
        ;