题解 | 判断质数

import math
number=int(input())
if number<=1:
    print('No')
elif number==2:
    print('Yes')
else:
    panduan=1
    for i in range(2,int(math.sqrt(number))+1):
        if number%i==0:
            print('No')
            panduan=0
            break
    if panduan:
        print('Yes')