题解 | #字符串中找出连续最长的数字串#

#include

#include

using namespace std;

int main() {

string a;

cin>> a;
int countNum = 0;
string recordNum = "";
string longestNum = "";


for (int i = 0; i < a.size(); ++i) {
    if (isdigit(a[i]) && recordNum == "") {
        recordNum += a[i];
    }
    else if (isdigit(a[i])) {

        if (recordNum[recordNum.size() - 1] + 1 == a[i]) {
            recordNum += a[i];
        }
        else {
            if (recordNum.size() > longestNum.size()) {
                longestNum = recordNum;
            }
            recordNum = "";
        }

    }
    else {
        continue;
    }

}

if (recordNum.size() > longestNum.size()) {
    longestNum = recordNum;
}

cout << longestNum << endl;
return 0;

}