题解 | #百钱买百鸡问题#

#include <iostream>
using namespace std;

int main() {
    int a,x,y,threez;
    while (cin >> a) { // 注意 while 处理多个 case
        for(threez=0;threez<=99;threez=threez+3)
        {
            for(x=0;100-x-threez>=0;x++)
            {
                y=100-x-threez;
                int z=threez/3;
                if(x*5+y*3+z==100)
                {
                    cout<<x<<" "<<y<<" "<<threez<<" "<<endl;
                }
            }
            
        }
    }
}
// 64 位输出请用 printf("%lld")