题解 | 求int型正整数在内存中存储时1的个数

#include <stdio.h>

int count(int n);

int main() 
{
    int n;
    scanf("%d",&n);

    int cnt = count(n);

    printf("%d",cnt);
}

int count(int n)
{
    int cnt = 0;
    while(n != 0)
    {
        cnt += n&1;
        n >>= 1;
    }

    return cnt;
}