题解 | #字符串加解密#

def check(a,b):
    L1 = "abcdefghijklmnopqrstuvwxyzABCDEFGHIJKLMNOPQRSTUVWXYZ0123456789"
    L2 = "BCDEFGHIJKLMNOPQRSTUVWXYZAbcdefghijklmnopqrstuvwxyza1234567890"
    result = ""
    if b == 1:
        for i in a:
            result += L2[L1.index(i)]
    elif b == -1:
        for i in a:
            result += L1[L2.index(i)]
    return result
while True:
    try:
        print(check(input(),1))
        print(check(input(), -1))
    except:
        break

# while True:
#     try:
#         s1=input()
#         s2=input()
#         l1=[]
#         l2=[]
#         for i in s1:
#             if i == 'z':
#                 l1.append('A')
#             elif i == 'Z':
#                 l1.append('a')
#             elif i.isupper() and i != 'Z':
#                 l1.append(chr((ord(i.lower())+1)))
#             elif i.islower() and i != 'z':
#                 l1.append(chr((ord(i.upper())+1)))
#             elif i in '0 1 2 3 4 5 6 7 8 9' and i != '9':
#                 l1.append(str(int(i)+1))
#             elif i == '9':
#                 l1.append('0')
#             else:
#                 l1.append(i)
#         for j in s2:
#             if j == 'a':
#                 l2.append('Z')
#             elif j == 'A':
#                 l2.append('z')
#             elif j.isupper() and j != 'A':
#                 l2.append(chr((ord(j)-1)).lower())
#             elif j.islower() and j != 'a':
#                 l2.append(chr((ord(j)-1)).upper())
#             elif j in '0 1 2 3 4 5 6 7 8 9' and j != '0':
#                 l2.append(str(int(j)-1))
#             elif j == '0':
#                 l2.append('9')
#             else:
#                 l2.append(j)
#         print(''.join(l1))
#         print(''.join(l2))
#     except:
#         break