题目:用两个栈来实现一个队列,完成队列的Push和Pop操作。 队列中的元素为int类型。
解答:
别人家的解答:
import java.util.Stack;
public class Solution {
Stack<Integer> stack1 = new Stack<Integer>();
Stack<Integer> stack2 = new Stack<Integer>();
public void push(int node) {
stack1.push(node);
}
public int pop() {
if (stack2.size() <= 0) {
while (stack1.size() != 0) {
stack2.push(stack1.pop());
}
}
return stack2.pop();
}}
我的解答:(写繁琐了,问题出在每次进出不是必须要交换两个栈的数据的,贴上以示警告)
public class Q_5 {
Stack<Integer> stack1 = new Stack<Integer>();
Stack<Integer> stack2 = new Stack<Integer>();
boolean isUse=false;
public void push(int node) {
while(isUse){
System.out.println("using");
}
isUse=true;
if(!stack2.isEmpty()){
stack1.empty();
while (!stack2.isEmpty()){
stack1.push(stack2.pop());
}
}
stack1.push(node);
isUse=false;
}
public int pop() {
while(isUse){
System.out.println("using");
}
isUse=true;
if(!stack1.isEmpty()){
stack2.empty();
while(!stack1.isEmpty()){
stack2.push(stack1.pop());
}
}
int result=stack2.pop();
isUse=false;
return result;
}
public static void main(String[] args) {
Q_5 test=new Q_5();
test.push(1);
test.push(2);
test.push(3);
test.push(4);
System.out.println(test.pop());
System.out.println(test.pop());
System.out.println(test.pop());
System.out.println(test.pop());
}}

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