题解 | #字符串加解密#

数字分为 000(billion),000(million),000(thound),000 四段,
three_digit 函数输出每一段的表达，function函数把四段链接起来

def three_digit(string):
    dic1 = {'1':'one','2':'two','3':'three','4':'four','5':'five','6':'six','7':'seven','8':'eight','9':'nine'}
    dic2 = {'10':'ten','11':'eleven','12':'twelve','13':'thirteen','14':'fourteen','15':'fifteen','16':'sixteen','17':'seventeen','18':'eighteen','19':'nineteen'}
    dic3 = {'2':'twenty','3':'thirty','4':'forty','5':'fifty','6':'sixty','7':'seventy','8':'eighty','9':'ninety'}
    result = ''
    if string[0] != '0':
        result = dic1[string[0]] + ' hundred '
        if string[1:] != '00':
            result += 'and '
    if string[1] == '1':
        result += dic2[string[1:]] + ' '
    if string[1] != '1' and string[1] != '0':
        result += dic3[string[1]] + ' '
    if string[1] != '1' and string[2] != '0':
        result += dic1[string[2]] + ' '
    return result
def function(string):
    number = string.rjust(12,'0')
    result = ''
    if number[0:3] != '000':
        result = three_digit(number[0:3]) + 'billion '
    if number[3:6] != '000':
        result = result + three_digit(number[3:6]) + 'million '
    if number[6:9] != '000':
        result = result + three_digit(number[6:9]) + 'thousand '
    if number[9:12] != '000':
        result = result + three_digit(number[9:12])
    return result
while True:
    try:
        print(function(input()))
    except:
        break