题解 | #字符串变形#

利用python的split函数即可，按照空格分开后倒着遍历，然后遍历的同时大小写转换即可。关键可能是要记得python的split函数，大小写转换函数upper()和lower()就行了。

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param s string字符串 
# @param n int整型 
# @return string字符串
#
class Solution:
    def trans(self , s: str, n: int) -> str:
        # write code here
        new = ''
        s = s.split(' ')
        for i in range(len(s)):
            tmp = s[len(s)-i-1]
            for j in range(len(tmp)):
                if tmp[j] >= 'A' and tmp[j] <= 'Z':
                    new = new+tmp[j].lower()
                elif tmp[j] >= 'a' and tmp[j] <= 'z':
                    new = new+tmp[j].upper()
            new = new+' '
        return new[:-1]




s = "This is a sample"
print(Solution().trans(s , 16))