select
SUBSTRING_INDEX(SUBSTRING_INDEX(PROFILE, ',', -2), ',', 1) as age,
count(*) as number
from user_submit
group by age;
substring_index() 受到上一题老哥的启发直接写出来了
select
SUBSTRING_INDEX(SUBSTRING_INDEX(PROFILE, ',', -2), ',', 1) as age,
count(*) as number
from user_submit
group by age;
substring_index() 受到上一题老哥的启发直接写出来了