import java.util.Scanner;
public class Main {
public static void main(String[] args) {
// TODO Auto-generated method stub
Scanner scanner=new Scanner(System.in);
int L=scanner.nextInt();
int m=scanner.nextInt();
int a[]=new int[L+1];
for (int i = 0; i < m; i++) {
int l=scanner.nextInt();
int r=scanner.nextInt();
for (int j = l; j <= r; j++) {
a[j]=1;
}
}
int count=0;
for (int i = 0; i < a.length; i++) {
if(a[i]==0) {
count++;
}
}
System.out.println(count);
}
}
本题其实不难,想到用数组赋值来做就好了,我一年前做这题是还在想着用数学计算做题,那就很麻烦。设置一个数组,把要修地铁的区域全部设为1,最后遍历统计非1的个数即可



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