题解 | #获得积分最多的人(二)#

select u.id,u.name,a.cnt from user u
join (select user_id,sum(grade_num) cnt
from grade_info group by user_id order by cnt desc) a
on u.id=a.user_id
join(select sum(grade_num) cnt
from grade_info group by user_id order by cnt desc limit 1) b
on a.cnt=b.cnt