C++简单代码/符合题意/3行:
class Solution { public: int Sum_Solution(int n) { n && (n += Sum_Solution(n - 1)); //A&&B 1.A为true,则计算并返回表达式B的bool值 return n; //2.A为false,则直接返回false } };
C++简单代码/符合题意/3行:
class Solution { public: int Sum_Solution(int n) { n && (n += Sum_Solution(n - 1)); //A&&B 1.A为true,则计算并返回表达式B的bool值 return n; //2.A为false,则直接返回false } };