LeetCode 0225. Implement Stack using Queues用队列实现栈【Easy】【Python】【栈】【队列】
Problem
Implement the following operations of a stack using queues.
- push(x) -- Push element x onto stack.
- pop() -- Removes the element on top of the stack.
- top() -- Get the top element.
- empty() -- Return whether the stack is empty.
Example:
MyStack stack = new MyStack(); stack.push(1); stack.push(2); stack.top(); // returns 2 stack.pop(); // returns 2 stack.empty(); // returns false
Notes:
- You must use only standard operations of a queue -- which means only
push to back
,peek/pop from front
,size
, andis empty
operations are valid. - Depending on your language, queue may not be supported natively. You may simulate a queue by using a list or deque (double-ended queue), as long as you use only standard operations of a queue.
- You may assume that all operations are valid (for example, no pop or top operations will be called on an empty stack).
问题
使用队列实现栈的下列操作:
- push(x) -- 元素 x 入栈
- pop() -- 移除栈顶元素
- top() -- 获取栈顶元素
- empty() -- 返回栈是否为空
注意:
- 你只能使用队列的基本操作-- 也就是
push to back
,peek/pop from front
,size
, 和is empty
这些操作是合法的。 - 你所使用的语言也许不支持队列。 你可以使用 list 或者 deque(双端队列)来模拟一个队列 , 只要是标准的队列操作即可。
- 你可以假设所有操作都是有效的(例如, 对一个空的栈不会调用 pop 或者 top 操作)。
思路
栈 队列
数据结构基础
Python3代码
class MyStack: def __init__(self): """ Initialize your data structure here. """ self.myStack = [] def push(self, x: int) -> None: """ Push element x onto stack. """ self.myStack.append(x) def pop(self) -> int: """ Removes the element on top of the stack and returns that element. """ # judge if it is empty if not self.empty(): return self.myStack.pop() def top(self) -> int: """ Get the top element. """ # judge if it is empty if not self.empty(): return self.myStack[-1] def empty(self) -> bool: """ Returns whether the stack is empty. """ return len(self.myStack) == 0 # Your MyStack object will be instantiated and called as such: # obj = MyStack() # obj.push(x) # param_2 = obj.pop() # param_3 = obj.top() # param_4 = obj.empty()