题解 | 最长公共前缀

#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param strs string字符串一维数组 
# @return string字符串
#
class Solution:
    def longestCommonPrefix(self , strs: List[str]) -> str:
        # write code here
        if not strs:
            return ""
        base = strs[0]
        for i in range(len(base)):
            for other in strs[1:]:
                if i >= len(other) or base[i] != other[i]:
                    return base[:i]
        return base