题解 | #统计成绩#

#include <stdio.h>
int main() 
{
    double n;

    scanf("%lf", &n);
    double maxx = 0, minn = 1e9, average = 0,
           sum = 0; //根据题目给的范围给定一个较大的min值
    for (int i = 0; i < n; ++i) {
        double x;
        scanf("%lf", &x); //每输入一次就进行一次判断和加和
        if (x > maxx)maxx = x;
        if (x < minn)minn = x;
        sum += x;
    }
    average = sum / n;
    printf("%.2f %.2f %.2f", maxx, minn, average);
    return 0;
}