解题思路:树的深度等于左右子数的最大值加一,若根节点为空,则返回0.
/**
public class TreeNode {
int val = 0;
TreeNode left = null;
TreeNode right = null;
public TreeNode(int val) {
this.val = val;
}
}
*/
public class Solution {
public int TreeDepth(TreeNode root) {
if(root==null){
return 0;
}
if(root.left!=null&&root.right!=null){
return Math.max(TreeDepth(root.left)+1,TreeDepth(root.right)+1);
}
else if(root.left==null&&root.right!=null){
return TreeDepth(root.right)+1;
}
else if(root.left!=null&&root.right==null){
return TreeDepth(root.left)+1;
}
return 1;
}
}
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