解题思路:树的深度等于左右子数的最大值加一,若根节点为空,则返回0.

/**
public class TreeNode {
    int val = 0;
    TreeNode left = null;
    TreeNode right = null;

    public TreeNode(int val) {
        this.val = val;

    }

}
*/
public class Solution {
    public int TreeDepth(TreeNode root) {
        if(root==null){
            return 0;
        }
        if(root.left!=null&&root.right!=null){
            return Math.max(TreeDepth(root.left)+1,TreeDepth(root.right)+1);
        }
        else if(root.left==null&&root.right!=null){
            return TreeDepth(root.right)+1;
        }
        else if(root.left!=null&&root.right==null){
            return TreeDepth(root.left)+1;
        }
        return 1;
    }
}