题解 | #字母统计#

#include<stdio.h>
#include <string.h>
int main() {
    char string[300];
    int count[26];//数组记录
    gets(string);
    for (int i = 0; i < 26; i++) //数组初始化
        count[i] = 0;

    for (int i = 0; i < strlen(string); i++) { //遍历字符串
        if (string[i] >= 'A'  && string[i] <= 'Z')
            count[(string[i] - 'A')]++;
    }
    for (int i = 0; i < 26; i++)
        printf("%c:%d \n", i + 'A', count[i]);

    return 0;
}