题解 | #链表的奇偶重排#

# class ListNode:
#     def __init__(self, x):
#         self.val = x
#         self.next = None
#
# 代码中的类名、方法名、参数名已经指定，请勿修改，直接返回方法规定的值即可
#
# 
# @param head ListNode类 
# @return ListNode类
#
class Solution:
    def oddEvenList(self , head ):
        # write code here
        p = head
        lis = []
        lis_j = []
        lis_o = []

        while(p):
            lis.append(p.val)
            p = p.next
        lis_j = lis[0::2]
        lis_o = lis[1::2]
        for i in lis_o:
            lis_j.append(i)

        p = head
        for i in range(len(lis_j)):
            p.val = lis_j[i]
            p = p.next
        return head