题解 | #杨辉三角的变形#

import java.util.*;
public class Main {
        public static void main(String[] args){
            Scanner sc = new Scanner(System.in);
            while(sc.hasNext()){
                int n = sc.nextInt();
                //找规律,对4取余,余数为1 3 结果是2,余数为0 ,结果是3 余数为2结果是4
                if(n==1 || n==2){
                    System.out.println(-1);
                    //continue;
                }else if(n%4==1 || n%4==3){
                    System.out.println(2);
                    //continue;
                }else if(n%4==0){
                    System.out.println(3);
                    //continue;
                }else if(n%4==2){
                    System.out.println(4);
                    //continue;
                }
            }
        }
}