思路:合并k个有序链表就是采用分治的思想,将K个链表两两合并;
import java.util.*;
/**
* Definition for singly-linked list.
* public class ListNode {
* int val;
* ListNode next;
* ListNode(int x) {
* val = x;
* next = null;
* }
* }
*/
public class Solution {
public ListNode mergeKLists(ArrayList<ListNode> lists) {
if(lists == null || lists.size() == 0){
return null;
}
return merge(lists, 0, lists.size()-1);
}
// 分治
private ListNode merge(ArrayList<ListNode> lists, int left, int right){
if(left == right){
return lists.get(left);
}
int mid = left + (right - left ) / 2;
ListNode node1 = merge(lists, left , mid);
ListNode node2 = merge(lists, mid + 1, right);
return mergeTwoList(node1, node2);
}
// 合并两个有序链表
private ListNode mergeTwoList(ListNode l1, ListNode l2){
ListNode dumpy = new ListNode(-1);
ListNode cur = dumpy;
while(l1 != null && l2 != null){
if(l1.val < l2.val){
cur.next = l1;
l1 = l1.next;
}else{
cur.next = l2;
l2 = l2.next;
}
cur = cur.next;
}
cur.next = l1 == null ? l2 : l1;
return dumpy.next;
}
}