A
#include<bits/stdc++.h>
#define int long long
using namespace std;
struct ios {
inline char read(){
static const int IN_LEN=1<<18|1;
static char buf[IN_LEN],*s,*t;
return (s==t)&&(t=(s=buf)+fread(buf,1,IN_LEN,stdin)),s==t?-1:*s++;
}
template <typename _Tp> inline ios & operator >> (_Tp&x){
static char c11,boo;
for(c11=read(),boo=0;!isdigit(c11);c11=read()){
if(c11==-1)return *this;
boo|=c11=='-';
}
for(x=0;isdigit(c11);c11=read())x=x*10+(c11^'0');
boo&&(x=-x);
return *this;
}
} io;
int n,k;
int a[20000007];
int l=1,r=1,ans=-1,tot;
signed main()
{
io>>n>>k;
for(int i=1;i<=n;i++) io>>a[i];
while(r<=n){
while(r<=n&&tot+a[r]<=k) tot+=a[r],r++;
if(tot==k) ans=max(ans,r-l);
tot-=a[l++];
}
cout<<ans<<"\n";
return 0;
}B
#include<bits/stdc++.h>
#define int long long
using namespace std;
int arr[11]={0,1,2,3,4,5,6,7,8,9};
int n,k,ans;
signed main()
{
cin>>n>>k;
do{
int h=0;
for(int i=0;i<n;i++)
h=h*10+arr[i];
if(h%k==0) ans++;
}while(next_permutation(arr,arr+n));
if(ans==0) ans=-1;
cout<<ans<<"\n";
return 0;
}C
#include<bits/stdc++.h>
using namespace std;
int n,m;
int h[1000006];
int main()
{
cin>>n>>m;
for(int i=1;i<=n;i++){
int x;
scanf("%d",&x);
h[i]=h[i-1]+x;
}
while(m--)
{
int x,y;
scanf("%d%d",&x,&y);
printf("%d\n",h[y]-h[x-1]);
}
return 0;
}D
...懒得打了...
E
#include<bits/stdc++.h>
using namespace std;
char a[20000007];
int k,n,l=1,flag,tot;
int get(int l,int r)
{
int MIN=1001,k;
for(int i=l;i<=r&&MIN!='0';i++){
if(a[i]<MIN){
k=i;
MIN=a[i];
}
}
return k;
}
int main()
{
scanf("%s",a+1);
n=strlen(a+1);
cin>>k;
if((double)clock()/CLOCKS_PER_SEC >0.5) return 0;
if(n==k){
puts("0");
return 0;
}
for(int i=k+1;i<=n&&tot<n-k;i++){
int k;
if(l!=i) k=get(l,i);
else k=i;
l=k+1;
if(a[k]=='0'&&!flag) continue;
flag=1;
putchar(a[k]);
tot++;
}
if(flag==0) cout<<"0";
return 0;
}F
#include<bits/stdc++.h>
using namespace std;
long long n;
int main()
{
cin>>n;
int k=log(n)/log(2)+1;
cout<<(1ll<<k)-1<<"\n";
return 0;
}G
python打的
import re
n=int(input())
ans=0
for i in range(n):
k=input()
if len(re.findall('A[ ]*l[ ]*a[ ]*n', k)):
ans+=len(re.findall('%',k))
print(ans)H&I
#include<bits/stdc++.h>
using namespace std;
int n;
struct oppo{
string s,m,x,h;
int k;
}a[1000006];
bool cmp(oppo a,oppo b)
{
if(a.s.length()!=b.s.length())
return a.s.length()<b.s.length();
if(a.s!=b.s)
return a.s<b.s;
return a.k<b.k;
}
int main()
{
cin>>n;
for(int i=1;i<=n;i++){
cin>>a[i].s>>a[i].m>>a[i].x>>a[i].h;
a[i].k=i;
}
sort(a+1,a+n+1,cmp);
for(int i=1;i<=n;i++){
cout<<a[i].s<<" "<<a[i].m<<" "<<a[i].x<<" "<<a[i].h<<"\n";
}
return 0;
}J
#include<bits/stdc++.h>
using namespace std;
int n;
int MIN=INT_MAX,k;
int main()
{
cin>>n;
for(int i=1;i<=n;i++){
int x;
scanf("%d",&x);
if(x<MIN){
k=i;
MIN=x;
}
}
cout<<k<<"\n";
return 0;
}
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