题解 | #特殊乘法#

#include <bits/stdc++.h>
using namespace std;
int main() {
    string str1;
    string str2;
    while (cin >> str1 >> str2) {
        int sum = 0;
        for (int i = 0; i < str1.size(); i++) {
            for (int j = 0; j < str2.size(); j++) {
                sum += (str1[i] - '0') * (str2[j] - '0');//ASLL码
            }
        }
        cout << sum << endl;
    }
    return 0;
}