import java.util.*;
import java.util.regex.*;
public class Main {
public static void main(String[] arg) {
Scanner sc = new Scanner(System.in);
while (sc.hasNext()) {
String str = sc.next();
if (getString(str, 0, 3)) {
System.out.println("NG");
continue;
}
if (str.length() <= 8) {
System.out.println("NG");
continue;
}
if (getMatch(str)) {
System.out.println("NG");
continue;
}
System.out.println("OK");
}
}
// 校验是否有重复子串-递归
private static boolean getString(String str, int l, int r) {
if (r >= str.length()) {
return false;
}
//021Abc9000
if (str.substring(r).contains(str.substring(l, r))) {
return true;
} else {
return getString(str, l + 1, r + 1);
}
}
// 检查是否满足正则
private static boolean getMatch(String str) {
int count = 0;
Pattern p1 = Pattern.compile("[A-Z]");
if (p1.matcher(str).find()) {
count++;
}
Pattern p2 = Pattern.compile("[a-z]");
if (p2.matcher(str).find()) {
count++;
}
Pattern p3 = Pattern.compile("[0-9]");
if (p3.matcher(str).find()) {
count++;
}
//存在非以上其他字符
Pattern p4 = Pattern.compile("[^a-zA-Z0-9]");
if (p4.matcher(str).find()) {
count++;
}
if (count >= 3) {
return false;
} else {
return true;
}
}
}