题解 | Old Bill

#include<stdio.h>
using namespace std;

int main() {
    int n;
    int x, y, z;
    int sum;
    int max = 0;
    //scanf("%d", &n);
    scanf("%d\n%d %d %d", &n,&x, &y, &z);
    for (int i = 1; i <= 9; i++) {
        for (int j = 0; j <= 9; j++) {
            sum = i * 10000 + x * 1000 + y * 100 + z * 10 + j;
            if (sum % n == 0) {
                max = sum > max ? sum : max;
            }

        }
    }
    if(max==0)printf("0");
    else printf("%d %d %d", max/10000, max%10, max / n);
    

    return 0;
}