题解 | #简单计算器#

#include <stdio.h>

int main(){
    double a,b;
    char c;
    scanf("%lf%c%lf",&a,&c,&b);
    switch(c){
        case '+':
            printf("%.4lf+%.4lf=%.4lf",a,b,a+b);
            break;
        case '-':
            printf("%.4lf-%.4lf=%.4lf",a,b,a-b);
            break;
        case '*':
            printf("%.4lf*%.4lf=%.4lf",a,b,a*b);
            break;
        case '/':
            if(b != 0.0){
                printf("%.4lf/%.4lf=%.4lf",a,b,a/b);
                break;
            }
            else{
                printf("Wrong!Division by zero!");
                break;
            }
        default:
            printf("Invalid operation!");
            break;
            
    }
    return 0;
}