题解 | #获取每个部门中当前员工薪水最高的相关信息#

select dept_no,emp_no,salary
from (select *,dense_rank()over(partition by dept_no order by salary desc) rank1
from (select dept_no,dept_emp.emp_no,salary
from dept_emp left join salaries on (dept_emp.emp_no = salaries.emp_no))t1)t1
where rank1 = 1