四舍五入

#include<bits/stdc++.h>

using namespace std;
const int N = 1e5+9;
double c[N]; 
int main()
{
   
	int n,m,p;
	cin>>n>>m>>p;
	for(int i=0;i<n;i++)
	{
   
	   double a,b;
	   scanf("%lf%lf",&a,&b);
	   c[i] = a*0.85 + b*0.15;
	}
	sort(c,c+n,greater<double>());
	double tmp = (c[m-1]- p*0.15)/0.85;
    if(tmp<=0) puts("0");
    else 
	printf("%.f\n",tmp+0.5);
	return 0;
}