题解 | #矩阵交换#

#include <stdio.h>
//BC108  矩阵交换
int main()
{
    //定义矩阵大小
    int n = 0;
    int m = 0;
    scanf("%d %d", &n, &m);
    //矩阵赋值
    int i = 0;
    int j = 0;
    int arr[n][m];
    for (i = 0; i < n; i++)
    {
        for (j = 0; j < m; j++)
        {
            scanf("%d", &arr[i][j]);
        }
    }
    //输入进行变幻的次数
    int k = 0;
    scanf("%d", &k);

    //分三种情况进行操作
    int a = 0;//a仅仅是用来循环次数
    while (a < k)
    {
        //先定义要执行的操作
        char ope = 0;
        //定义具体位置
        int x = 0;
        int y = 0;
        while (getchar() != '\n');//清理缓冲区
        scanf("%c %d %d", &ope, &x, &y);
        switch (ope)
        {
        case 'r'://行操作，只需关心列
            for (j = 0; j < m; j++)
            {
			  	//一定要注意是x-1，y-1你的具体行数和数组下标差1
                int temp = arr[x-1][j];
                arr[x-1][j] = arr[y-1][j];
                arr[y-1][j] = temp;
            }
            break;
        case 'c'://列操作，只需关心行
            for (i = 0; i < n; i++)
            {
                int temp = arr[i][x-1];
                arr[i][x-1] = arr[i][y-1];
                arr[i][y-1] = temp;
            }
            break;
        default://不进行操作
            break;
        }
        a++;
    }
    //输出变换后的矩阵
    for (i = 0; i < n; i++)
    {
        for (j = 0; j < m; j++)
        {
            printf("%d ", arr[i][j]);
        }
        printf("\n");
    }
    return 0;
}