题解 | #链表中环的入口结点#

/*
struct ListNode {
    int val;
    struct ListNode *next;
    ListNode(int x) :
        val(x), next(NULL) {
    }
};
*/
class Solution {
public:
    ListNode* EntryNodeOfLoop(ListNode* pHead) {
        ListNode* fast = pHead,*slow = pHead;
        while(fast&&fast->next)
        {
            fast = fast->next->next;
            slow = slow->next;
            if(fast == slow)
            {
                slow = pHead;
                while(fast!=slow)
                {
                    fast = fast->next;
                    slow = slow->next;
                }
                return fast;
            }
        }
        return nullptr;
    }
};